Question

Divide and state the remainder

(I need help solving)

(a^3 + 6a^2 - 11a -38) ÷ (a+7)

Answer 1

Answer:

remainder=-10

Step-by-step explanation:

a^3+6a^2-11a-38=a^3+7a^2-a^2-7a-4a-28-10=a^2(a+7)-a(a+7)-4(a+7)-10=(a+7)*(a^2-a-4)-10

or you can find remainder replacing a with -7:

-7^3+6*-7^2+7*11-38= -10

Answer 2

Answer:

• - 10

Step-by-step explanation:

(a³ + 6a² - 11a -38) ÷ (a+7) = a² - a - 4 rem (-10)

a³ + 7a²

      - a² - 11a

      - a² - 7a

              - 4a - 38

             - 4a - 28

                      -10