Answer:
-1
Step-by-step explanation:
Set y=0.
[tex]5 {x}^{2} + 7x + 2 = 0 \\ x = \frac{ - 7± \sqrt{ {7}^{2} - 4(5)(2)} }{2(5)} \\ x = \frac{ - 7± \sqrt{ 9} }{10} \\ x = \frac{ - 7±3}{10} \\ x = - \frac{2}{5} \: \: \: \: or \: \: \: \: - 1[/tex]
The x-intercepts are - 0.4 and - 1.
The other x-intercept is - 1.