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Find the equation of the line that passes through the point (2,-6) and is perpendicular to the line y=1/4x-2.

Respuesta :

Answer:

Step-by-step explanation:

The standard form of an equation for a straight line is y=mx+b, where m is the slope and b is the y-intercept (the value of y when x = 0).

The line we want is perpendicular to y=1/4x-2.  A perpendicular line will have a slope that is the negative inverse of the reference line, so it will have a slope of -4.  That gives us:

y = -4x + b

We can find b by entering the given point, (2,-6) and solving for b:

y = -4x + b

-6 = -4*(2) + b

-6 = -8 + b

b = 2

The equation is y = -4x + 2

Check it by graphing (DESMOS works well).  Attached.

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