Question

Juan has x quarters and y dimes, having a minimum of 16 coins worth at most $3 combined. No less than 4 of the coins are quarters. Solve this system
of inequalities graphically and determine one possible solution.

Answer 1

Answer:

• See below

Step-by-step explanation:

Quarter - 25¢, dime - 10¢, total - $3 = 300¢

Inequalities:

• x + y ≥ 16
• 25x + 10y ≤ 300
• x ≥ 4

See attached for graphical solution. There are many solutions.

Possible one solution:

• 5 quarters and 17 dimes