Question

Carl is boarding a plane. He has 222 checked bags of equal weight and a backpack that weighs 4 \text{ kg}4 kg4, start text, space, k, g, end text. The total weight of Carl's baggage is 35 \text{ kg}35 kg35, start text, space, k, g, end text.
Write an equation to determine the weight, www, of each of Carl's checked bags.Find the weight of each of his checked bags.

Answer 1

Answer:

$w=15.5$

$w=\frac{31}{2}$

Equation:

$2w+4=35$

Step-by-step explanation:

$2w+4=35\\2w=31\\w=15.5$

Hidden Steps:

1) Subtract 4 on each side of the equation:

$2w+4-4=21\\35-4=31$

2) Divide each side of the equation by 2:

$2w$ ÷ $2=w$

$31$ ÷ $2=15.5-or-\frac{31}{2}$

Answer 2

Answer:

Equation: 2w + 4 = 35

Weight: 15.5

Step-by-step explanation:

Let w be the weight of each checked bag.

The weight of Carl's 2 checked bags is 2w kg. The weight of his backpack is 4kg. The total weight of his baggage is 2w + 4 kg.

Since his total baggage weighs 35 kg, let us set this to 35:

2w + 4 = 35

Now you solve:

1. 2w + 4 = 35

2. 2w = 35-4

3. 2w = 31

4. w = 31/2

5. w = 15.5

Therefore, the equation is 2w + 4 = 35 and the solution to " w " is 15.5 kg.

Hopefully this helps you understand more!