PLEASE HELP ASAP POINTS!!

Write the equation of a quadratic function that has been shifted 3 units down, to the right 2 units, and
stretched vertically by a factor of 5.

Respuesta :

Answer:

y = 5(x² - 2) - 3

Step-by-step explanation:

    In y = a(x² - b) + c, a is the stretch factor, -b is the horizontal, and c is the vertical

    You did not give us the parent function, so I am going to assume it is y = x²

         y = x²

    3 units down means the function will be moved 3 units down, so it will look like:

         y = (x²) - 3

    Shifted 2 units to the right will result in a -2, so we add that in:

         y = (x² - 2) - 3

    The stretch factor is 5, which goes in front of everything else, multiplying the quadratic,

         y = 5(x² - 2) - 3

Have a nice day!

    I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)

- Heather

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