Im confused on this. Michael has some coins in his pocket consisting of dimes, nickels, and pennies. He has two more nickels than dimes, and three times as many pennies as nickels. How many of each kind of coin does he have if the total value is $0.52?

Respuesta :

Answer:

Using a system of equations, it is found that he has 2 dimes, 5 nickels and 12 pennies.

In the system of equations, I am going to say that:

x is the number of dimes.

y is the number of nickels.

z is the number of pennies.

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Two more nickels than dimes, thus:

Three times as many pennies as nickels, thus:

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A dime is worth $0.1, a nickel is worth $0.05, and a penny is worth $0.01. Total of $0.52, thus:

Solving for x:

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Solving for y and z:

He has 2 dimes, 5 nickels and 12 pennies.