Question

A 20 kg block (4) rests on a frictionless table;
a cord attached to the block extends
horizontally to a pulley at the edge of the
table. A 10 kg mass (B) hangs

Answer 1

Answer:

Explanation:

F = ma

a = F/m

a = 10(9.8) / (10 + 20)

a = 3.3 m/s²

(T)ension in the cord

20(3.3) = 65 N