Question

Follow the steps to solve the equation. Solve 3 sqrt x^2-7= 3 sqrt 2x+1

To solve the given equation,________ both sides.

100 points

Answer 1

Answer:

x = -2,4

(disclaimer plugging in -2 will give an imaginary number)

Step-by-step explanation:

3$\sqrt{x^2-7}$=3$\sqrt{2x+1}$

Divide both sides by 3

$\sqrt{x^2-7}$=$\sqrt{2x+1}$

Square both sides to cancel square roots

$x^2-7=2x+1$

Move all the terms to the left side

$x^2-2x-8=0$

Use the quadratic formula

$x=\frac{2 +/- \sqrt{(-2)^2-4(1)(-8)}}{2(1)}$

which gives x= -2,4

OR factor the quadratic

(x-4)(x+2)=0

x= -2,4

Answer 2

Answer:

part one is cube

part two is x=8.25

Step-by-step explanation:

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