Question

8. A car jumps a river that is 6m wide and lands

on the right side 2m lower than the left side?


A. How much time is the car in the air? Hint: how much time did it take to drop down 2m?

B. How fast horizontally must the car have been traveling to clear the river

Answer 1

Answer:

A

Explanation: I dont really understand. But,Most likely A

Answer 2

Answer:

Explanation:

If we assume the car is a point mass in a frictionless world

and v is the initial velocity and the launch is from horizontal ground with no initial vertical velocity

The time to drop 2 m will be

s = ½at²

t = √(2s/a)

t = √(2(2)/9.8)

t = 0.638876...

t = 0.64 s

v = d/t

v = 6 / 0.638876...

v = 9.39148

v = 9.4 m/s