Respuesta :

Okay, assuming you have some idea on the atomic spectrum of Hydrogen,

1λ=R.[1n22−1n21]  

is how you determine the wavelength of the photon emitted, where  R  is the Rydbergs constant and  n2  is final shell,  n1  is the initial shell

To find the photon with maximum energy, you have to find a photon with the least value of  λ  which is same as having most value of  1λ  so you need to find values of  n2,n1  such that

1n22−1n21  is minimum as  R  is just a constant,

To do this we need least value of  n2  and max value of  n1  

And for shells the values range from 1 to infinity,

Hence value of  n2= 1, n1= infinity

So the electron must go from infinity to 1st shell

This is essentially the same as the atom capturing a free, i.e unbounded electron that then transitions to the first shell.

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