Question

Two submarines are underwater and approaching each other head-on. Sub А
has a speed of 12 m/s and sub B has a speed of 8 m/s. Sub A sends out a 1550
Hz sonar wave that travels at a speed of 1522 m/s. What is the frequency
detected by sub B?

Answer 1

Answer:

speed=0.3*100=30m/s

speed=0.1*50=5m/s

frequency=20/0,5=40HZ

frequency=80/0.2=400HZ

frequency=120/0.4=300HZ

wavelength=340/440=0.77m

wavelength=340/880=0.39m

wavelength=250/400=0.63m

speed=2*50=100m/s

speed=0.5*100=50m/s

Explanation:

Answer 2

Answer:

Explanation:

f = 1550((1522 + 8)/(1522 - 12))

f = 1,570.529... 1571 Hz