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Answer:
If you have a fourth degree polynomial whose only 0 is 3, then you can say your polynomial takes the form of:
f(x) = (x-3)(x-3)(x-3)(x-3)
= (x2 - 6x + 9)(x2 - 6x + 9)
= x4 - 6x3 + 9x2 -6x3 + 36x2 - 54x + 9x2 - 54x + 81
= x4 - 12x3 + 54x2 - 108x + 81
There's your fourth degree polynomial. It has a "quadruple root" of 3. No other zeros (either real or imaginary) exist in this function.
Step-by-step explanation:
There's your fourth-degree polynomial. It has a "quadruple root" of 2.No other zeros (either real or imaginary) exist in this function.
What is polynomial?
A polynomial is defined as the sum of the same variables having different powers.
If you have a fourth-degree polynomial whose only 0 is 2, then you can say your polynomial takes the form of:
f(x) = (x-2)(x-2)(x-2)(x-2)
f(x) = (x² - 4x + 4)( x² - 4x + 4)
f(x) = x⁴ - 4x³ + 4x² - 4x² + 16x² -16x +4x²-16x + 16
f(x) = x⁴ - 4x³ +20x² -32x +16
There's your fourth-degree polynomial. It has a "quadruple root" of 2.No other zeros (either real or imaginary) exist in this function.
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