Answer:
A)
Line 1 slope = 3
Line 2 slope = 3
Line 3 slope = 3/-9
B)
Line 1 and 2 are parallel
Line 1 and 3 are Perpendicular
Line 2 and 3 are Perpendicular
Step-by-step explanation:
Use the formula [tex]\frac{y2-y1}{x2-x1}[/tex]
Line 1, we do [tex]\frac{(4)-(-2)}{(-1)-(-3)}[/tex] = [tex]\frac{6}{2}[/tex] = [tex]3[/tex]
Line 2, we do [tex]\frac{(1)-(-2)}{(0)-(-1)} =\frac{1+2}{1} =\frac{3}{1} = 3[/tex]
Line 3, we do [tex]\frac{(-3)-(-6)}{(-6)-(3)} = \frac{-3+6}{-6-3} = \frac{3}{-9}[/tex]
now put the lines into point slope formula to get the line. : y-y1 = m (x-x1)
line 1 is y-4 = 3 (x+1)
line 2 is y-1 = 3 (x+0)
line 3 is y+3 = -3/9(x+6)
this is what the graphs look like
red is line 1
green is line 2
black is line 3
