Question

Q1: An enzyme hydrolyzed a substrate concentration of 0.03
mmol/L ,the initial velocity was 1.5x10^-3 mmol/L.min-1 and
the maximum velocity was 4.5x10^-3 mmol/L.min-1.
Calculate the Km value.

Answer 1

An enzyme hydrolyzed a substrate concentration of 0.03 mmol/L with an initial velocity of 1.5 × 10⁻³ mmol/L.min and a maximum velocity of 4.5 × 10⁻³ mmol/L.min. The Michaelis constant is 0.06 mM.

An enzyme hydrolyzed a substrate concentration of 0.03 mmol/L ([S]).

The initial velocity (v) was 1.5 × 10⁻³ mmol/L.min and the maximum velocity ($v_{max}$) was 4.5 × 10⁻³ mmol/L.min.

We can calculate the Michaelis constant (Km) using the Michaelis-Menten equation.

$v = \frac{v_{max}[S]}{Km+[S]} \\\\Km = \frac{v_{max}[S]}{v} - [S] = \frac{(4.5 \times 10^{-3}mmol/L.min )(0.03mmol/L)}{1.5\times 10^{-3}mmol/L.min} - 0.03mmol/L = 0.06mM$

An enzyme hydrolyzed a substrate concentration of 0.03 mmol/L with an initial velocity of 1.5 × 10⁻³ mmol/L.min and a maximum velocity of 4.5 × 10⁻³ mmol/L.min. The Michaelis constant is 0.06 mM.

Learn more: https://brainly.com/question/19381399