Constant rates are used to illustrate linear functions.
- The average rate of change is $9.0 per hour
- The function that models the table is: [tex]\mathbf{f(x) = 9x }[/tex]
- The amount earned in 7.5 hours is $67.5
(a) The average rate of change
This is calculated using:
[tex]\mathbf{Rate = \frac{y_2 -y_1}{x_2 -x_1}}[/tex]
So, we have:
[tex]\mathbf{Rate = \frac{31.5-22.50}{3.5 - 2.5}}[/tex]
[tex]\mathbf{Rate = \frac{9}{1.0}}[/tex]
[tex]\mathbf{Rate = 9.0}[/tex]
Hence, the average rate of change is $9.0 per hour
(b) A function that models the table of values
Let x represent hours, and y represent the earnings.
So, we have:
[tex]\mathbf{y =m (x - x_1) + y_1}[/tex]
Where:
m =Rate = 9.0
So, we have:
[tex]\mathbf{y = 9(x - 2.5) + 22.5}[/tex]
Expand
[tex]\mathbf{y = 9x - 22.5 + 22.5}[/tex]
[tex]\mathbf{y = 9x }[/tex]
Represent as a function
[tex]\mathbf{f(x) = 9x }[/tex]
Hence, the function that models the table is: [tex]\mathbf{f(x) = 9x }[/tex]
(c) Amount earned for 7.5 hours
This means that x = 7.5
So, we have:
[tex]\mathbf{f(7.5) = 9 \times 7.5 }[/tex]
[tex]\mathbf{f(7.5) = 67.5}[/tex]
Hence, the amount earned in 7.5 hours is $67.5
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