Answer:
In a certain experiment, a sample of helium in a vacuum system was compressed at 25 degrees C from a volume of 6000.0 mL to a volume of 240.0 mL where its pressure was found to be 32.0 mmHg. What is the original pressure of helium?
Boyle’s Law states that, for an ideal gas at a constant temperature, pressure is inversely proportional to volume. In other words, the pressure x volume is a constant.
Therefore p1 x v1 = p2 x v2.
Therefore v1/v2 = p2/p1
Applying the figures from the question: 6000/240 = 32/p1, or p1 = 32 x 240/6000
Doing the arithmetic, the original pressure p1 = 1.28 mm Hg
Explanation:
