The point on the circumference of the circle with the equation (x+10)^(2)+(y+1)^(2) = 25 is (-6 , 2).
If a circle O has radius of r units length and that it has got its center positioned at (h, k) point of the coordinate plane,
then, its equation is given as:
(x-h)^2 + (y-k)^2 = r^2
The given equation is
(x+10)^(2)+(y+1)^(2)=25
Where,
h = - 10
k = -1
r = 5
If x = -6 and y = 2
then the given equation of circle is stidfy the given points.
Hence, the point on the circumference of the circle with the equation (x+10)^(2)+(y+1)^(2) = 25 is (-6 , 2).
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