Answer:
5.25MJ
Explanation:
Considering the weight of the skydiver constant over the descent -ie, the acceleration of gravity not decreasing as you go up the earth surfice, the work is simply the product of the two:
[tex]w= \vec F\cdot \vec x = Fx = 1050\times 5000 = 5,250,000 = 5.25MJ[/tex]