Respuesta :

Paounn

Answer:

There are none.

Step-by-step explanation:

No calculus involved:

The line, in slope-intercept form, has equation [tex]y=-10x+17[/tex], ie is always decreasing (easy to spot applying the definition)

Meanwhile, [tex]y=e^{5x}[/tex] is always increasing over its domain.

At no point the tangent will be decreasing.

Let's use calculus

We are to solve the equation [tex]y'(x) = -10 \rightarrow 5e^{5x} = -10 \rightarrow e^{5x}=-2[/tex] which has no real solutions.

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