Question

2(4 - 3x) ≤ 4(x - 5), where x ∈ W​

Answer 1

$\large\underline{\sf{Solution-}}$

Given:

$\rm\longmapsto 2(4-3x)\leq 4(x-5), x\in\mathbb{W}$

$\rm\longmapsto 8-6x\leq 4x-20$

$\rm\longmapsto 8-6x+6x\leq 4x-20+6x$

$\rm\longmapsto 8\leq 10x-20$

$\rm\longmapsto 8+20\leq 10x-20+20$

$\rm\longmapsto 28\leq 10x$

$\rm\longmapsto 10x\geq 28$

$\rm\longmapsto \dfrac{10x}{10}\geq \dfrac{28}{10}$

$\rm\longmapsto x\geq 2\dfrac{4}{5},x \in\mathbb{W}$

$\large\underline{\sf{Answer-}}$

Therefore:

$x=\{3,4,5,6,...\infty\}$