Question

A chemist needs a 60% acid solution. How many liters of a 10% acid solution and an 80% acid solution must be mixed together to obtain 126 L of the 60% acid solution? Enter only the number of liters of the 10% solution that is needed.

Answer 1

Using proportions, it is found that 36 liters of the 10% solution that is needed.

The final solution has 60% of acid in 126 L. It is formed by:

• x liters of a 10% acid solution.
• 126 - x liters of a 80% acid solution.

Hence, the equation that we use to solve for x is:

$0.1x + 0.8(126 - x) = 0.6(126)$

$0.1x - 0.8x = 0.6(126) - 0.8(126)$

$0.7x = 25.2$

$x = \frac{25.2}{0.7}$

$x = 36$

Hence, 36 liters of the 10% solution that is needed.

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