Question

4(x-3) < x+3, Where x ∈ W
Please help me​

Answer 1

$\large\underline{\sf{Solution-}}$

Given:

$\rm\longmapsto 4(x-3)<x+3, x\in \mathbb{W}$

$\rm\longmapsto 4x-12<x+3$

$\rm\longmapsto 4x-12-x<x+3-x$

$\rm\longmapsto 3x-12<3$

$\rm\longmapsto 3x-12+12<3+12$

$\rm\longmapsto 3x<15$

$\rm\longmapsto \dfrac{3x}{3}<\dfrac{15}{3}$

$\rm\longmapsto x<5, x\in\mathbb{W}$

$\large\underline{\sf{Answer-}}$

Therefore:

$\rm\longmapsto x=\{0,1,2,3,4\}$