Based on the complete information, we can conclude that the productivity objective is not better than $75000 per employees.
From the complete information, the number of employees is 29, standard deviation is 18968.117 and the mean is 75500. Then, the t-value will be:
= (75500 - 75000) / (18967.17 / ✓20)
= 0.1179
The table value of t at 5% level of significance will be 1.7291. Therefore, the null hypothesis will be rejected.
In conclusion, the productivity objective is not better than $75000 per employee.
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