Question

7x=4x^2-1
complete the square! (help me please!!)

Answer 1

Answer:

Step-by-step explanation:

$7x=4x^{2} -1$

$7x - (4x^{2} -1)= 0$

$7x - 4x^{2} +1 = 0$

$-4x^{2} +7x+1=0$

$4x^{2} -7x-1=0$

use the quadratic formula: $x = \frac{ -b \frac{+}{-} \sqrt{b^{2} -4ac }}{2a}$

a = 4  b = -7  c = -1

·$x = \frac{-(-7)\frac{+}{-} \sqrt{(-7)^{2}-4 times 4(-1)} }{2 times 4}$

$x = \frac{7\frac{+}{-} \sqrt{49-16} }{8}$

$x = \frac{7\frac{+}{-} \sqrt{65} }{8}$

hope this helped!

mark me brainliest :D