Question

What is the value of 2x{6+[12/(3+1)}-1

Answer 1

Start with innermost parenthesis-(3+1)=4
then the next-12/4=3
then add 6=9
then multiply by the 2=18
then subtract 1

=17

Answer 2

The value of an expression is calculated by simplifying the expression.

The value of the expression is 17

The expression is given as:

$\mathbf{2 \times \{6+[12 \div (3+1)\}-1}$

Simplify 3 + 1

$\mathbf{2 \times \{6+[12 \div (3+1)\}-1 = 2 \times \{6+[12 \div 4\}-1}$

Divide

$\mathbf{2 \times \{6+[12 \div (3+1)\}-1 = 2 \times \{6+[3\}-1}$

Remove square bracket

$\mathbf{2 \times \{6+[12 \div (3+1)\}-1 = 2 \times \{6+3\}-1}$

Add

$\mathbf{2 \times \{6+[12 \div (3+1)\}-1 = 2 \times \{9\}-1}$

Remove curly bracket

$\mathbf{2 \times \{6+[12 \div (3+1)\}-1 = 2 \times 9-1}$

Multiply

$\mathbf{2 \times \{6+[12 \div (3+1)\}-1 = 18-1}$

Subtract

$\mathbf{2 \times \{6+[12 \div (3+1)\}-1 = 17}$

Hence, the value of the expression is 17

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