Question

the nth term of a sequence is n(n-8)÷√n+3
find the 1st and 6th terms

Answer 1

Answer:

-4 and -2✓6+3

Step-by-step explanation:

use pemdas

1(1-8)÷✓1 + 3

-7÷1+3

-4

6(6-8)÷✓6+3

-12÷✓6+3

multiply fraction by ✓6 on bottom and top to get rid of square root on bottom

-12✓6÷6+3

divide -12 by 6 and put radical next to it

-2✓6+3