Question

To avoid an accident, a car decelerates at 0.50 / 2 for 3.0 and covers 15 of road. What was the car’s initial velocity?

Answer 1

We have that for the Question"To avoid an accident, a car decelerates at 0.50 / 2 for 3.0 and covers 15 of road. What was the car’s initial velocity?" it can be said that  the car’s initial velocity is

• u=4.625

From the question we are told

To avoid an accident, a car decelerates at 0.50 / 2 for 3.0 and covers 15 of road. What was the car’s initial velocity?

Generally the Newton's equation for the Motion   is mathematically given as

$s=ut+1/2at^2\\\\Therefore\\\\15=ut+1/2(0.50/2)3^2\\\\u=\frac{15-(1/2(0.50/2)3^2)}{3}$

u=4.625

Therefore

the car’s initial velocity is

• u=4.625

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