Considering the reaction stoichiometry, the total number of moles of NO produced from 0.25 moles of O₂ is 0.2 moles.
The balanced reaction is:
4 NH₃ + 5 O₂ → 4 NO + 6 H₂O
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
Then you can apply the following rule of three: if by stoichiometry 5 moles of O₂ produce 4 moles of NO, 0.25 moles of O₂ will produce how many moles of NO?
[tex]amount of moles of NO= \frac{0.25 moles of O_{2} x4 moles of NO}{5 moles of O_{2} }[/tex]
amount of moles of NO= 0.2 moles
Finally, the total number of moles of NO produced from 0.25 moles of O₂ is 0.2 moles.
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