Question

A pet store has ​11 puppies, including ​2 poodles, 4 ​terriers, and 5 retrievers. If Rebecka and​ Aaron, in that​ order, each select one puppy at random with replacement​ (they may both select the same​ one), find the probability that Rebecka selects a terrier and Aaron selects a retriever.

Answer 1

Answer:  $10/91$

Step-by-step explanation:

Since there are 14 puppies total and 5 of them are poodles, there 5 chances out of 14 for Rebecka to choose a poodle. Since the choices are done without replacement, there are now 13 left and 4 possibilities from which Aaron to choose. Since we want to calculate the probability that BOTH of them choose a poodle, we use the multiplication rule which tells us to multiply the individual probabilities.

$(5/14)(4/13) = 10/91$

Answer 2

The probability that Rebecka selects a terrier and Aaron selects a retriever is $\frac{20}{121}$.

What is probability?

Probability is the chance that something will happen, or how likely it is that an event will occur.

What is the formula for probability?

The formula for the probability is given by

$P(E) = \frac{\ number \ of favorable\ outcomes }{total\ number \ of \ outcomes}$

Where,

P(E) is the probability of an event.

According to the given question.

Total number of puppies = 11

⇒ Total number of outcomes = 11

Total number of poodles puppies = 2

Total number of terries puppies = 4

Total number of retrievers puppies = 5

Now,

The probability that Rebecka selects a terrier puppy = $\frac{4}{11}$

And, the probability that Aaron selects a retriever puppy = $\frac{5}{11}$

Therefore, the probability that Rebecka selects a terrier and Aaron selects a retriever = $\frac{4}{11} \times\frac{5}{11} = \frac{20}{121}$

Hence, the probability that Rebecka selects a terrier and Aaron selects a retriever is $\frac{20}{121}$.

Find out more information about probability here :

https://brainly.com/question/11234923

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