The distance between point A and B is 60 m
Since the Mars rover traveled from point A to point B at the speed of v = 4 cm/sec in time, t.
The distance travelled from point A to B is d = vt = 4t
Also, on the return trip the rover travels at a speed of v' = 2.5 cm/sec. Since the travel time on the return trip is increased by 15 minutes, the rover travels on the return trip in a time t' = t + 15 min = t + (15 × 60 s) = t + 900 s. The distance travelled back also equals d.
So, d = v't
= 2.5t'
= 2.5(t + 900)
Since d = 4t = 2.5(t + 900)
4t = 2.5t + 2250
4t - 2.5t = 2250
1.5t = 2250
t = 2250/1.5
t = 1500 s
So, the distance between point A and B is d = 4t
= 4 cm/s × 1500 s
= 6000 cm
= 60 m
the distance between point A and B is 60 m
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