The time of motion of the car before coming to a full stop is 6.67 s.
The car length that should be kept between you and the car is 138.33 m.
The given parameters;
The time of motion of the car before coming to a full stop is calculated as follows;
[tex]v = u + at\\\\when \ the \ car \ stops , \ v = 0\\\\0 = u + at\\\\0 = 40 -6t\\\\6t = 40\\\\t = \frac{40}{6} = 6.67 \ s[/tex]
The distance traveled by the car before coming to a full stop;
[tex]v^2 = u^2 + 2as\\\\0 = u^2 + 2as\\\\0 = 40^2 -2(6)s\\\\0 = 40^2- 12s\\\\12s = 1600\\\\s = \frac{1600}{12} \\\\s = 133.33 \ m[/tex]
The car length that should be kept between you and the car is calculated as;
car length in front of you = 5 m + 133.33 m = 138.33 m
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