Question

As part of an experiment, a small amount of a certain substance was placed in a container at 7:00 in the morning .The substance doubled in volume even in exactly 1 hour the container became full of the substance. How many minutes after 7:00 was the container 1/8full of the substance? 10 20 30 40

Answer 1

Answer:

7.5 minutes ( 7 minutes and 30 seconds )

Step-by-step explanation:

1 (full) in 60 minutes

1/8 full in (60 * 1/8) minutes

= 7.5 minutes

Answer 2

Using the exponential model, the number of minutes in which the container would be 1/8 full will be 30 minutes.

Let the initial volume = x

• Doubling time = 10 minutes
• Time until full = 60 minutes

We could model the scenario using an exponential function thus :

• $1 = A(2)^{6}$

Where ;

• 1 = fraction when full
• A = initial volume
• Time until full = 60 /10 = 6
• Rate = 2 (double)

We can then calculate the initial volume :

1 = 64A

A = 1/64

A = 0.015625

We can then calculate the time taken for container to be 1/8 full :

$\frac{1}{8} = \frac{1}{64}(2)^{t}$

$8 = 2^{t}$

$2^{3} = 2^{t}$

3 = t

Hence, the time taken is (3 × 10) = 30 minutes.

Learn more : https://brainly.com/question/10725996