Question

4. Line p contains point (6, -5) and is perpendicular to line q. The equation for line qis y = 3x + 5.
Write an equation for line p.
Part I: Find the slope of line q. (1 point)




i give brainlist

Answer 1

Answer:

Slope of line q: 3

Slope of line p: -1/3

Equation of line p: y = -1/3x - 3

Step-by-step explanation:

Finding the slope of line p:

The slope of line q is 3 (as given in y = 3x + 5)

For finding the slope of a line perpendicular to line q, both lines must have a product of -1, as shown below:

m₁m₂ = -1

m₁ in the current case is 3. Hence,

3m₂ = -1

m₂ = -1/3

Hence, the slope of line p is -1/3

Substituting the value of m into 'y=mx+c':

y = -1/3x + c

Substituting (6,-5) into the above equation:

-5 = -1/3 * 6 + c

-5 = -2 + c

c = -3

Hence,

y = -1/3x - 3

Hope this helps and be sure to have a wonderful time ahead at Brainly! :D