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HELPPP!!! WILL MARK BRAINLIEST!!! 10 PTS

Find an equation for the graph sketched below:

HELPPP WILL MARK BRAINLIEST 10 PTS Find an equation for the graph sketched below class=

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Answer:

Plot the coordinate points and connect them with a smooth curve.

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The equation for the graph is y = [tex]2(3)^{x} -5[/tex]  .

What are Exponential Equations?

An exponential equation is an equation with exponents where the exponent (or) a part of the exponent is a variable.

Standard exponential equation :

y = [tex]a(b)^{x} + k[/tex]

where a is the initial value

b represents the base of the exponential function

x will represent the input of the function

y = k is the single horizontal asymptote

k is  constant

According to the question

The figure in the graph is an exponential graph .

To derive the equation

we will use Standard exponential equation :

y = [tex]a(b)^{x} + k[/tex]  

Now,

There are two points in graph

(0.-3) and (1,1)

k = - 5  ( distance from 0)

now ,

Substituting the values

y = [tex]a(b)^{x} + k[/tex]  

y = [tex]a(b)^{x} -5[/tex]

for point   (0.-3)

-3 = [tex]a(b)^{0} -5[/tex]  

-3 = [tex]a -5[/tex]

a = 2  

for point   (1,1)

1 = [tex]2(b)^{1} -5[/tex]  

1 = 2b - 5

b = 3

Therefore , equation of exponential graph is  

y = [tex]2(3)^{x} -5[/tex]  

Hence ,The equation for the graph is y = [tex]2(3)^{x} -5[/tex]  .

To know more about Exponential Equations here:

https://brainly.com/question/23729449

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