Answer:
y=3/2x+3/2
Step-by-step explanation:
point at (-6,-5)
slope = m = 3/2
y = mx+b
(-6)=(3/2)(-5)+b >>> substituting x & y to solve for b
-6 = (-15/2)+b >>> simplify previous equation
-6 + (15/2) = b >>> isolate and solve for m
3/2 = b
therefore, the equation of the line passing through the point (-6,-5) with a slope of 3/2 is y=(3/2)x+(3/2)
