Answer:
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Explanation:
The useful energy generated by the machine having an efficiency of 15% and an energy input of 300 J is 45 J
Efficiency = 15% = 0.15
Work input = 300 J
The useful energy generated (i.e work output) by the machine can be obtained as follow:
[tex]Efficiency = \frac{workout}{workin} * 100\\\\0.15 = \frac{Workout}{300}[/tex]
Cross multiply
Work output = 0.15 × 300
Therefore, the useful energy generated by the machine is 45 J
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