Question

A coordinate plane with a line passing through (negative 3, 0), (0, negative 2) and (3, negative 4).
What is the equation of the graphed line written in standard form?

2x + 3y = –6
2x + 3y = 6
y equals negative StartFraction 2 Over 3 EndFraction x minus 2.
y equals StartFraction 2 Over 3 EndFraction x minus 2.

Answer 1

Answer:

2x+3y=-6

Step-by-step explanation:

the intercepts are (-3,0) (x intercept) and (0,-2) (y intercept)

this means that when x = 0, y = -2 and when y = 0, x = -3.

the last two are not in standard form, so we can eliminate those.

the answer also cannot be the second one because both intercepts are negative. when we solve it, the intercepts would be (3,0) and (0,2). the answer must be 2x+3y=-6.

sorry for the late reply!