Answer:
Explanation:
Remark
The question really is how long does the projectile stay in the air if it was just dropped from a height of 46 meters.
Givens
vi = 0
a = 9.81 m/s^2
h = 46 m
t = ?
Solution
d = vi*t + 1/2 a t^2
46 = 0 + 1/2 * 9.81 * t^2 multiply both sides by 2
92 = 9.81 * t^2 divide by 9.81
t^2 = 9.38 Take the square root of both sides
sqrt(t^2) = sqrt(9.38)
t = 3.06 seconds.
In 3.06 seconds the object will hit the ground, thus stopping it. How far horizontally does it go in that time.
d = r * t
d=?
r = 102 m/s
t = 3.06 seconds
d = 102 * 3.06
d = 312.4 meters.
