Question

An ellipse or hyperbola uses the general form
Ar? + Cy? + Da + Ey + F
= 0. Solving for 5 unknowns (A, B, C, D, E, F)
requires 5 equations, needs 5 points given. But if one of the coefficients is
divided out (A or C), then only 4 coefficients remain and only 4 points are needed,
1? + Cy? + Da + Ey + F = 0
Given 4 points on a vertical ellipse (-1, 2.517), (0, 1.933), (1, 0.65), and (-4.449, 0).
Select the missing coefficients (answers have been rounded to the nearest tenth).

Answer 1

The missing coefficients are the following:

$C = 0.2$, $D = 3.1$, $E = 2.6$ and $F = -5.9$.

In this question we need to generate a system of linear equations by using the set of points described in the statement:

$6.335\cdot C -D +2.517\cdot E + F = -1$ (1)

$3.736\cdot C + 1.933\cdot E + F = 0$ (2)

$0.423\cdot C + D + 0.65\cdot E + F = -1$ (3)

$-4.449\cdot D + F = - 19.794$ (4)

The solution to this system of equations, that is, the missing coefficients, is presented below:

$C = 0.2$, $D = 3.1$, $E = 2.6$, $F = -5.9$

The missing coefficients are the following:

$C = 0.2$, $D = 3.1$, $E = 2.6$ and $F = -5.9$.

We kindly invite to check this question on systems of linear equations: https://brainly.com/question/20379472

Nota - The question presents typographical mistakes. The corrected statement is presented below:

An ellipse or hyperbola uses the general form $A\cdot x^{2} + C\cdot y^{2}+D\cdot x + E\cdot y + F = 0$- Solving for 5 unknowns ($A, C, D, E, F$) requires 5 equations, needs 5 points given. But if one of the coefficients is divided out ($A$ or $C$), then only 4 coefficients remain and only 4 points are needed:

$x^{2} + C'\cdot y^{2} + D'\cdot x + E'\cdot y + F' = 0$

Given four points on a vertical ellipse (-1, 2.517), (0, 1.933), (1, 0.65) and (-4.449, 0)

Select the missing coefficients (answer have been rounded to the nearest tenth).