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A 75kg person is seated on a Ferris wheel 15m from the center axis. If the person presently experiences 1500N of centripetal force, what must be the angular velocity of the Ferris wheel

A 75kg person is seated on a Ferris wheel 15m from the center axis If the person presently experiences 1500N of centripetal force what must be the angular veloc class=

Respuesta :

This question involves the concepts of centripetal force and angular velocity.

The angular velocity of the Ferris wheel is found to be "1.15 rad/s".

The centripetal force in terms of angular velocity is given by the following formula:

[tex]F=mr\omega^2[/tex]

where,

F = centripetal force = 1500 N

m = mass of person = 75 kg

r = radius = 15 m

ω = angular velocity = ?

Therefore,

[tex]1500\ N=(75\ kg)(15\ m)\omega^2\\\\\omega=\sqrt{\frac{1500\ N}{(75\ kg)(15\ m)}}[/tex]

ω = 1.15 rad/s

Learn more about centripetal force here:

brainly.com/question/11324711?referrer=searchResults

The attached picture shows the centripetal force.

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