A 75kg person is seated on a Ferris wheel 15m from the center axis. If the person presently experiences 1500N of centripetal force, what must be the angular velocity of the Ferris wheel

This question involves the concepts of centripetal force and angular velocity.
The angular velocity of the Ferris wheel is found to be "1.15 rad/s".
The centripetal force in terms of angular velocity is given by the following formula:
[tex]F=mr\omega^2[/tex]
where,
F = centripetal force = 1500 N
m = mass of person = 75 kg
r = radius = 15 m
ω = angular velocity = ?
Therefore,
[tex]1500\ N=(75\ kg)(15\ m)\omega^2\\\\\omega=\sqrt{\frac{1500\ N}{(75\ kg)(15\ m)}}[/tex]
ω = 1.15 rad/s
Learn more about centripetal force here:
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The attached picture shows the centripetal force.