Answer:
The coordinates for the given triangle are A(6,3), B(6,-3) and C(-2,-3), respectively.
Step-by-step explanation:
Let us translate this triangle by -6 units along the x-axis and +3 units along the y-axis. This means that 6 will be subtracted from each of the abcissas (x-points) and 3 will be added to each ordinates (y-points). Hence, our translated triangle will have the following coordinates: A'(0,6), B'(0,0) and C'(-8,0), respectively.
Now to prove that both triangles are congruent, we use the SSS postulate, which states that:
"If three sides of one triangle are congruent to three sides of another triangle, then the triangles are congruent."
Distance between two point P1 and P2 will be:
Now using distance formula to find sides of triangle ABC and triangle A'B'C'.
For Triangle ABC:
|AB| =
|AC| =
|BC| =
For Triangle A'B'C':
|A'B'| =
|A'C'| =
|B'C'| =
Hence, as the distances are equal, the two triangles are congruent by SSS postulate. Hope this helped! :)