Question

Ara constant temperature, the pressure on 8.0 L of a gas is increased from 1 atm to 4 atm. What
will be the new volume of the gas?

Answer 1

Answer:

2L

Explanation:

WE ARE SQUEEZING THE VOLUME DOWN BY INCREASING THE PRESSURE BY A FACTOR OF 4, THEREFOR THE NEW VOLUME WILL BE (1/4) OF THE OLD VOLUME OR 8x(1/4)= 2L

Answer 2

At constant temperature, the pressure on 8.0 L of a gas is increased from 1 atm to 4 atm. The new volume of the gas will be 2 L.

What is Boyle's Law ?

Boyle's law is a gas law which states that at constant temperature (T), the pressure (P) of a given quantity of a gas varies inversely with its volume (V) occupied by it.  

According to the Boyle's Law:

PV = constant

Thus,

P₁V₁ = P₂V₂

where,

P₁ is the initial pressure

V₁ is the initial volume

P₂ is the final pressure

V₂ is the final volume

Here,

P₁ = 1 atm , P₂ = 4 atm

V₁ = 8.0 L , V₂ = ?

Now, put the values in above equation we get

P₁V₁ = P₂V₂

1 atm × 8.0 L = 4 atm × V₂

V₂ = $\frac{1\ atm \times 8.0\ L}{4\ atm}$

V₂ = 2 L

Thus, from the above conclusion we can say that at constant temperature, the pressure on 8.0 L of a gas is increased from 1 atm to 4 atm. The new volume of the gas will be 2 L.

Learn more about Boyle's Law here: brainly.com/question/1696010

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