Question

PLS HELPPPPP

When 0.06 moles of lead(II) nitrate are dis- solved in enough water to make 656 mililiters of solution, what is the molar concentration of nitrate ions?
Answer in units of M.

Answer 1

Answer:

M=0.09 mol/L

Explanation:

M=mol/volume

M=0.06 mol/0.656 L(convert 656 ml to L by ÷ by 1000)

M=0.09 mol/L