Question

Consider cashiers and people who line up for the cashiers in a supermarket. In how many ways can 3 people line up for 3 cashiers?

Answer 1

3 people can line up for 3 cashiers in 6 ways.

This is a permutation type of question. Formula for permutation is given as

nPr = $\frac{n!}{(n-r)!}$

where

P = permutation

n = total number of objects = 3

r = total number of objects selected = 3

nPr = $\frac{3!}{(3-3)!}$

nPr = $\frac{3 * 2 * 1}{1 }$

nPr = $\frac{6}{1}$

nPr = 6

therefore the number of ways needed is 6.

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