Solve the inequality.
4x + 3 < 7 or 3x – 8 > 7
-
x < [?] or x > [

Answer:
[tex]4x + 3 < 7 \\ 4x + 3 - 3 < 7 - 3 \\ 4x < 4 \ \\ 4x \div 4 < 4 \div 4 \\ x < 1[/tex]
[tex]3x - 8 > 7 \\ 3x - 8 + 8 > 7 + 8 \\ 3x > 15 \\ 3x \div 3 > 15 \div 3 \\ x > 5[/tex]