Question

Determine the amount of grams present in
3.25x1024 atoms of Lithium.

Answer 1

Answer:

Explanation:

Molar mass of Lithium is 6.9410 g/mol.

This means 1 mol of Li atoms weigh 6.9410 g

In 1 mol 6.022 x 10 ^ 23 atoms should be present

So, in 6.9410g , there should be 6.022 x 10 ^ 23 atoms.

So weight of 1 atom = a =  6.9410  g / (6.022 x 10^ 23)

To find weight of 3.25 x 10 ^ 24 atoms we have to multiply a by 3.25 x 10^ 24

So you will get the answer as

[6.9410  g / (6.022 x 10^ 23)]   x 3.25 x 10^ 24

= 37.46 g