so 2.46 X 10^28 contains (2.46 X 10^28)/(6.02 X 10^23) =
(2.46 X 10 X 10^27)/ (6.02 x(10^23) = (24.6/6.02) X 10^ (27-23)=
4.09 X 10^4 = 40,900
Answer:
4.09 X 10^4 = 40,900 moles
Explanation:
How many moles of Magnesium(Mg) are
in 2.46 x 10^28 atoms of Magnesium?
PLEASE LEARN THIS FUNDAMENTAL RULE OF CHEMISTRY...1 MOLE OF ANYTHING CONTAINS AVOGADROS NUMBER OF PARTICLES}
6.02 X 10^23.09
so 2.46 X 10^28 contains in moles(2.46 X 10^28)/(6.02 X 10^23) =
(2.46 X 10 X 10^27)/ (6.02 x(10^23) = (24.6/6.02) X 10^ (27-23)=
4.09 X 10^4 = 40,900 moles
