Respuesta :

so 2.46 X 10^28 contains (2.46 X 10^28)/(6.02 X 10^23) =

(2.46 X 10 X 10^27)/ (6.02 x(10^23) = (24.6/6.02) X 10^ (27-23)=

4.09 X 10^4 = 40,900

Answer:

4.09 X 10^4 = 40,900 moles

Explanation:

How many moles of Magnesium(Mg) are

in 2.46 x 10^28 atoms of Magnesium?

PLEASE LEARN THIS FUNDAMENTAL RULE OF CHEMISTRY...1 MOLE OF ANYTHING CONTAINS AVOGADROS NUMBER OF PARTICLES}

6.02 X 10^23.09

so 2.46 X 10^28 contains in moles(2.46 X 10^28)/(6.02 X 10^23) =

(2.46 X 10 X 10^27)/ (6.02 x(10^23) = (24.6/6.02) X 10^ (27-23)=

4.09 X 10^4 = 40,900 moles

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