A hockey puck with mass 170 g is attached to a rope of length 65.0 cm and swung in a horizontal circle against the ice at a rate of 53.0 rpm. Assuming the ice is frictionless, what is the tension in the rope?

Respuesta :

This question involves the concepts of tension force and centripetal force.

The tension force in the rope is "3.4 N".

In this scenario, the centripetal force shall be acting as the tension force of the rope. Because in order for the puck to move in a circular path, the tension force in the rope must be equal to the centripetal force.

[tex]Tension\ Force = Centripetal\ Force\\F = \frac{mv^2}{r}[/tex]

where,

F = tension force = ?

m = mass of puck = 170 g = 0.17 kg

r = radius of path = length of rope = 65 cm = 0.65 m

v = linear speed of puck = r(angular speed) = (0.65 m)(53 rpm)[tex](\frac{2\pi\ rad}{1\ rev})(\frac{1\ min}{60\ s})[/tex]

v = 3.61 m/s

Therefore,

[tex]F = \frac{(0.17\ kg)(3.61\ m/s)^2}{0.65\ m}[/tex]

F = 3.4 N

Learn more about centripetal force here:

brainly.com/question/11324711?referrer=searchResults

The attached picture shows the centripetal force.

Ver imagen hamzaahmeds
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