The number of moles present in 29.5 grams of argon is 0.74 mole.
The atomic mass of argon is given as;
Ar = 39.95 g/mole
The number of moles present in 29.5 grams of argon is calculated as follows;
39.95 g ------------------------------- 1 mole
29.5 g ------------------------------ ?
[tex]= \frac{29.5}{39.95} \\\\= 0.74 \ mole[/tex]
Thus, the number of moles present in 29.5 grams of argon is 0.74 mole.
"Your question seems to be missing the correct symbol for the element"
Argon = Ar
Learn more here:https://brainly.com/question/4628363